SOLUTION:
Congratulation Winners
Consider the first
block as shown with output as 'x'.
Assuming the drop
across each diode is considered to be 0.7.
Case 1:
A=0, B=0
Both the diodes conduct
and hence the voltage at x=0.7 i.e.,
equivalent to logic '0'.
Case 2:
A=0, B=1 / A=1,
B=0 (logic '1' represents +5V)
Only one diode conducts
while other is reverse biased. So the voltage at x=0.7 ≈ logic '0'.
Case 3:
A=1, B=1
Both the diodes are
reverse biased and hence they act as open connections resulting in voltage as x=5V ≈ logic '1'.
Hence the first block
is found to be behaving as an logical AND gate. Therefore x=A.B.
Similarly considering x and C to be input to next identical
connection whose output is y, we find
its operation to be similar as first
block i.e., y=x.C=A.B.C.
The last gate in above diagram is a logical NOT
gate, hence provides complimentary output, i.e.,
Hence we infer that,
the above logic circuit is a 3-input-NAND gate.
COTW
- 2 RESULTS:
NAME SECTION POINTS
Aneesha
J D'Souza III
Sem A 2
Anushree
Shenoy III
Sem A 2
Disha
Ramesh Shet III
Sem A 2
Abhilash III Sem A 1
Anjana
R III Sem A 1
Deepa
S III
Sem A 1
Akshaya
S Palan III Sem A 1
Pooja
Poojary III Sem B 2
Priyanka
Shetty III
Sem B 2
Kshetha
Rainal III
Sem B 1
Mefil
D'Souza III Sem B 1
Mohith
Prabhu M III Sem B 1
Pratheek
P B III Sem B 1
Pallavi
Bhatka S III
Sem B 1
Shwetha III Sem C 2
Sukanya
Pai III Sem C 2
Suraksha Shetty III Sem C 2
Shreshta III
Sem C 1

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